Given the equation of the line:
[tex]\text{ y = -}\frac{1}{2}x\text{ + 1}[/tex]The equation is in slope-intercept form, y = mx + b.
Where,
m = slope
b = y-intercept
Thus,
The slope of the line, m = -1/2
The y-intercept, b = 1
Graphing the equation, let's determine at least two points of the line.
Let's use conditions when x = 0 and y = 0,
Point 1: At x = 0,
y = -1/2(x) + 1
y = -1/2(0) + 1
y = 1
(0,1)
Point 2: At y = 0,
y = -1/2(x) + 1
0 = -1/2(x) + 1
1/2(x) = 1
1/2(x)(2) = (1)(2)
x = 2
(2,0)
We get,
