timothy566 timothy566

03-01-2017
Mathematics

contestada

use substitution to solve s+a=4 and 35+5a=2550

Respuesta :

03-01-2017

35+5(4-s)=2550
35+20-5s=2550
55-5s=2550
-55 -55
-5s = 2495
s = - 499

-499 + a = 4
+499 +499
a = 503

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olemakpadu olemakpadu

03-01-2017

s + a = 4

35 + 5a = 2550

From the second equation:

35 + 5a = 2550

5a = 2550 - 35

5a = 2515

a = 2515/5

a = 503

From s + a = 4

s + 503 =4

s = 4 - 503

s = -499

Therefore a = 503, s = -499

Answer Link

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