Katiecastro Katiecastro
  • 02-12-2016
  • Mathematics
contestada

How do I find dy/dx of the equation 4x^3-3xy^2+y^3=28 at the point (3,4)?

Respuesta :

MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 12-12-2016
To get the dy/ dx of the equation 4x^3-3xy^2+y^3=28 at the point (3,4), get the first derivative then substitute the given value. Y = 4x^3-3xy^2+y^3=28 Dy / dx = (2x / y) + 1 Substitute the given Dy /dx = ( (2*3)/ 4) + 1 Dy/dx = 5/2

 

Answer Link

Otras preguntas

I need help with this problem ASAP!
Read and choose the correct option. ________ bajo. Él es Usted tienes Tu amigo tiene Ella es
what is the value of x in mathematics ​
Why were people intersected in exploring and settling in western Virginia. Plz 50 points
What does FTTB mean?
Helpppppp!!!!!!!!!! Plsss
Guys can you please help me with this?? Thanks to whoever helps me
Delegates at the Constitutional Convention were ultimately able to compromise by adopting the A) Virginia Plan B) New Jersey Plan C) South Carolina Plan D) Conn
IN the running jump, S'Mira jumped 16 feet and 9 inches.How many inches did she jump? {One foot equals 12 inches} will mark brainliest!
Helppp plzzz I have to submit it today. Look at the figure. D 480 E 73) w G F How can you determine the measures of ZDGE and GF.