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  • 01-11-2020
  • Mathematics
contestada

m2+12=48 solve the quadratic equations using any of the methods​

Respuesta :

limichael2005 limichael2005
  • 01-11-2020

Answer:

Ok:

Step-by-step explanation:

So, you would have:

[tex]m^2+12=48[/tex]

or

[tex]m^2+12-48=0[/tex]

or

[tex]m^2-36=0[/tex]

You know that [tex]a^2-b^2 = (a+b)(a-b)[/tex]

so you get the factorized form of

[tex](m+6)(m-6)=0[/tex].

Giving us two solutions of m=6 or -6.

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