When ever I encounter problem like this, I make the equation become: z = anything buy z. First, you want to get 2/5 to the other side, to do so, you need to multiply 5/2 on both side. then you are left with z+1=5/2 y. Then you subtract 1 from both sides to make z on its own. The answer should be z = 3/2y or z= 1[tex] \frac{1}{2} [/tex]y
2/5(z+1)=y 2/5(z+1)5/2=5/2y z+1=5/2y z+1-1=5/2y-1 z=3/2y or z=1[tex] \frac{1}{2} [/tex]y
