Answer:
A) inside the circle
Step-by-step explanation:
equation of the circle is:
[tex](x-a)^{2} + (y-b)^{2} = r^{2}[/tex]
where (a,b) is center of the circle and r is radius so
[tex]x^{2} + y^{2} = r^{2}[/tex] now plug in given point to find the radius
[tex](6)^{2} + (-4)^{2} = r^{2}[/tex]
36 +16 = 52 so
r = [tex]\sqrt{52}[/tex] ≈ 7.2 or [tex]r^{2} =52[/tex]
when you plug point (√2 , -7) into equation of the circle
(√2)^2 + (-7)^2 = 2 +49 =51
51 is less than 52 so this is inside of the circle
