Answer:
Force, [tex]F=6\times 10^9\ N[/tex]
Explanation:
Given that,
Charge 1, [tex]q_1=3\ C[/tex]
Charge 2, [tex]q_2=2\ C[/tex]
Distance between charges, d = 3 m
We need to find the force between charges. The electric force between charges is given by :
[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]
k is electrostatic constant
[tex]F=\dfrac{9\times 10^9\times 3\times 2}{(3)^2}\\\\F=6\times 10^9\ N[/tex]
So, the force between charges is [tex]6\times 10^9\ N[/tex]. Hence, this is the required solution.
