Answer:
4.7 x 10⁵ J
Explanation:
m = mass of the car = 925 kg
d = distance traveled parallel to incline = 207 m
θ = angle of the slope = 14.5 deg
Force applied to move the car up is given as
F = mg Sinθ eq-1
minimum work needed is given as
W = F d
using eq-1
W = mgd Sinθ
inserting the values
W = (925)(9.8)(207) Sin14.5
W = 4.7 x 10⁵ J
