sydneelittle3851 sydneelittle3851
  • 02-07-2018
  • Mathematics
contestada

Let the random variable x be equally likely to assume any of the values 1/12, 1/6, or 1/4. determine the mean and variance of x.

Respuesta :

sqdancefan
sqdancefan sqdancefan
  • 02-07-2018
The mean of x is
  (1/3)(1/12 + 1/6 + 1/4) = 1/6

The mean of the squares is
  (1/3)((1/12)² + (1/6)² + (1/4)²) = 7/216

The variance is the difference between the mean square and the square of the mean.
  7/216 -(1/6)² = 1/216

The mean of x is 1/6.
The variance of x is 1/216.
Answer Link

Otras preguntas

I'm having trouble finding the answers. I've read the text over a dozen times. Please help!
A 0.50 m solution of an acid ha has ph = 2.24. what is the value of ka for the acid?
Why should a person that takes an HIV test today also take one in 3 months? Some one please help me find the right answer please.
How do you learn to speck German ?
Meredith uses a rule to write the following sequence of numbers. 14 3/10 13 4/5 13 3/10 . what rule did meredith use
Explain why locations near a large body of water generally have higher average temperatures in the winter and lower average temperatures in the summer
a bag weighs 336 ounces when full and 171 ounces when half full. what does the bag weigh when empty?
Mountain high ice cream company transferred $61,000 of accounts receivable to the prudential bank
Briefly explain in one paragraph, how geography, warfare, art and architecture impacted the ancient Minoan and Mycenaean cultures?
How many valence electrons is each element trying to obtain?